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6n^2-89n-1127=0
a = 6; b = -89; c = -1127;
Δ = b2-4ac
Δ = -892-4·6·(-1127)
Δ = 34969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{34969}=187$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-89)-187}{2*6}=\frac{-98}{12} =-8+1/6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-89)+187}{2*6}=\frac{276}{12} =23 $
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